Jorney of 480km was covered in 9hours.some part of journey was coverd 45km/hour and remaining at 60km/hour . Find how much part of journey was covered at the speed of 60km/hour ?
swaraj2004:
superb and hard one
Answers
Answered by
3
Total Distance = 480km
Total time = 9 hours
Distance travelled during speed 45km/h be x.
So,
Distance travelled during speed 60km/h wipp be 480-x
So time = dis/speed
9 = x/45 + (480-x)/60
9 = 4x + 3(480-x) / 180
1620 = 4x + 1440 -3x
x = 1620-1440
x= 180km
So distance travelled during 45 km/h is 180km
So distance during 60km/h is 480-180= 300km
Total time = 9 hours
Distance travelled during speed 45km/h be x.
So,
Distance travelled during speed 60km/h wipp be 480-x
So time = dis/speed
9 = x/45 + (480-x)/60
9 = 4x + 3(480-x) / 180
1620 = 4x + 1440 -3x
x = 1620-1440
x= 180km
So distance travelled during 45 km/h is 180km
So distance during 60km/h is 480-180= 300km
Answered by
0
Let he covered x km distance at speed of 45km/hr so rest (480-x)km distance he covered at speed of 60km/hr.
APQ , x/45 + (480-x) /60 =9
x = 180 after solving the equation
180 km distance covered at speed of 45km/hr and rest 300km distance covered at speed of 60km/hr
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