Math, asked by sudhiyuva2005, 5 months ago

Jose and William are running on a circular track. Jose is running on the outer
edge of the track and covers a distance of 695.2 meters in one round. William is running on the inner edge of the track and covers a distance of 580.8 meters in one round
Find the width of the track. (Assume n = 22/7)

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Answers

Answered by nl829395
2

Answer:

Step-by-step explanation:

Jose is running on the outer track and cover a distance of 695.2 m in one round, it means outer circumference of track is 695.2 m

similarly the inner circumference of track is 580.8 m

let outer radius of circular track be r_{1} and inner radius be r_{2}

according to the question,

                 2\pi r_{1} = 695.2 m

                     r_{1} = 110.6 m

                 2\pi r_{2} = 580.8 m

                     r_{2} = 92.4 m

width of track = r_{1} - r_{2}

                       = 110.6-92.4 m

                       = 18.2 m

If you still have doubt then ask me!

Answered by Anonymous
12

\huge\underline\mathfrak\pink{♡Answer♡}

Jose is running on the outer track and cover a distance of 695.2 m in one round, it means outer circumference of track is 695.2 m

similarly the inner circumference of track is 580.8 m

let outer radius of circular track be r_{1} and inner radius be r_{2}

according to the question,

                 2\pi r_{1} = 695.2 m

                     r_{1} = 110.6 m

                 2\pi r_{2} = 580.8 m

                     r_{2} = 92.4 m

width of track = r_{1} - r_{2}

                       = 110.6-92.4 m

                       = 18.2 m

If you still have doubt then ask me!

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