Question

Jose and William are running on a circular track. Jose is running on the outer
edge of the track and covers a distance of 695.2 meters in one round. William is running on the inner edge of the track and covers a distance of 580.8 meters in one round
Find the width of the track. (Assume n = 22/7)

pl guys pl pl pl pl pl pl pl pl give a correct answer.....​

Answer 1

$\huge\underline\mathfrak\pink{♡Answer♡}$

Jose is running on the outer track and cover a distance of 695.2 m in one round, it means outer circumference of track is 695.2 m

similarly the inner circumference of track is

580.8 m

Let outer radius of circular track be $r_{1}$ and inner radius be $r_{2}$

★According to the question,

                 $2\pi r_{1} = 695.2$ m

                     $r_{1} =$ $110.6$ m

                 $2\pi r_{2} =$ $580.8$ m

                     $r_{2} =$ $92.4$ m

width of track = $r_{1} - r_{2}$

                       = $110.6-92.4$ m

                       = $18.2$ m

Answer 2

Jose is running on the outer track and cover a distance of 695.2 m in one round, it means outer circumference of track is 695.2 m

similarly the inner circumference of track is

580.8 m

Let outer radius of circular track be r_{1}r

1

and inner radius be r_{2}r

2

★According to the question,

2\pi r_{1} = 695.22πr

1

=695.2 m

r_{1} =r

1

= 110.6110.6 m

2\pi r_{2} =2πr

2

= 580.8580.8 m

r_{2} =r

2

= 92.492.4 m

width of track = r_{1} - r_{2}r

1

−r

2

= 110.6-92.4110.6−92.4 m

= 18.218.2 m