Joseph and Peter can complete a work in 20 hours and 25 hours respectively
Find : (1) work done by both together in 4 hrs.
(ii) work left after both worked together for 4 hrs.
(ii) time taken by Peter to complete the remaining work.
Answers
Answer:
1.work done by both together in 4 hrs is 9/25
2.from 5 hrs
Answer:
Hey there,
Step-by-step explanation.
(i) Time taken by joseph complete a work = 20 hours.
Time taken by peter to complete a work = 25 hours
Joseph's one hour work = 1/20
Peter's one hour work=1/25
So both joseph' and peter's work in one hour = 1/20 + 1/25
taking LCM = ( 5+ 4 )/ 100 = 9/100
(i) work done by both together in 4 hrs = 9/100×4=9/25
(ii) Time taken by joseph complete a work = 20 hours.
Time taken by peter to complete a work = 25 hours
Joseph's one hour work = 1/20
Peter's one hour work=1/25
So both joseph' and peter's work in one hour = 1/20 + 1/25
taking LCM = ( 5+ 4 )/ 100 = 9/100
work done by both together in 4 hrs = 9/100×4=9/25
Work left after both worked together for 4 hrs =1−
25
9
=
25
(25−9)
= 16/25