Question

Joseph and Peter can complete a work in 20 hours and 25 hours respectively
Find : (1) work done by both together in 4 hrs.
(ii) work left after both worked together for 4 hrs.
(ii) time taken by Peter to complete the remaining work.​

Answer 1

Answer:

1.work done by both together in 4 hrs is 9/25

2.from 5 hrs

Answer 2

Answer:

Hey there,

Step-by-step explanation.  

(i) Time taken by joseph complete a work = 20 hours.  

Time taken by peter to complete a work = 25 hours  

Joseph's one hour work = 1/20

Peter's one hour work=1/25

So both joseph' and peter's work in one hour = 1/20 + 1/25  

taking LCM = ( 5+ 4 )/ 100 = 9/100

(i) work done by both together in 4 hrs = 9/100×4=9/25

(ii) Time taken by joseph complete a work = 20 hours.  

Time taken by peter to complete a work = 25 hours  

Joseph's one hour work = 1/20

Peter's one hour work=1/25

So both joseph' and peter's work in one hour = 1/20 + 1/25  

taking LCM = ( 5+ 4 )/ 100 = 9/100

work done by both together in 4 hrs =   9/100×4=9/25

Work left after both worked together for 4 hrs =1−  

25

9

​  

=  

25

(25−9)

​  

=  16/25

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