Question

Joseph had a reel of wire. After using 35/6 meter of the wire he was left with 7/4 meters of the wire .how much wire did he have in the beginning?

Answer 1

Answer:

Wire used = 35/6 m

Wire left = 7/4 m

Total wire have in the beginning = 35/6+7/4m

=35*2+7*3/12m

=70+21/12m

=91/12mAns

Answer 2

Joseph had $\frac{91}{12}$ meter of wire in the beginning.

Step-by-step explanation:

Consider the provided information.

Joseph used 35/6 meter of the wire and he was left with 7/4 meters of the wire.

Let x represents the wire he have in the beginning.

Thus, x must be equal to the sum of used wire and remaining wire.

$x=\frac{35}{6}+\frac{7}{4}$

The LCM of 6 and 4 is 12.

$x=\frac{35\times2+7\times3}{12}$

$x=\frac{70+21}{12}$

$x=\frac{91}{12}$

Hence, he had $\frac{91}{12}$ meter of wire in the beginning.

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