Physics, asked by lolh48295, 1 month ago

Joseph is jogging on 300m's straight road. In 2m and 30s he ran A point to B point and In 1 m he ran 100m back at c point.
A)what is a speed of Joseph to ran A point to B point.
B)what is speed of Joseph to ran B point to C point.

Answers

Answered by meghashyju81
1

From pont A to B

Distance covered=300m

Displacement=300m

Time taken=2 min 30 sec=(2×60)+30=150 sec

Average speed=  

Timetaken

Distance covered

=  

150

300

=2 m/sec

Average velocity=  

Timetaken

Displacement

=  

150

300

=2 m/sec

From point A to C

Distance covered=300+100=400m

Displacement=300−100=200m

Time taken=3 min 30 sec=(3×60)+30=210 sec

Average speed=  

Timetaken

Distance covered

=  

210

400

=1.90 m/sec

Average velocity=  

Timetaken

Displacement

=  

210

200

=0.95 m/sec

Answered by Akshara6c
0

Answer:

From pont A to B

Distance covered=300m

Displacement=300m

Time taken=2 min 30 sec=(2×60)+30=150 sec

Average speed=

Timetaken

Distance covered

=

150

300

=2 m/sec

Average velocity=

Timetaken

Displacement

=

150

300

=2 m/sec

From point A to C

Distance covered=300+100=400m

Displacement=300−100=200m

Time taken=3 min 30 sec=(3×60)+30=210 sec

Average speed=

Timetaken

Distance covered

=

210

400

=1.90 m/sec

Average velocity=

Timetaken

Displacement

=

210

200

=0.95 m/sec

Explanation:

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