Joseph is jogging on 300m's straight road. In 2m and 30s he ran A point to B point and In 1 m he ran 100m back at c point.
A)what is a speed of Joseph to ran A point to B point.
B)what is speed of Joseph to ran B point to C point.
Answers
From pont A to B
Distance covered=300m
Displacement=300m
Time taken=2 min 30 sec=(2×60)+30=150 sec
Average speed=
Timetaken
Distance covered
=
150
300
=2 m/sec
Average velocity=
Timetaken
Displacement
=
150
300
=2 m/sec
From point A to C
Distance covered=300+100=400m
Displacement=300−100=200m
Time taken=3 min 30 sec=(3×60)+30=210 sec
Average speed=
Timetaken
Distance covered
=
210
400
=1.90 m/sec
Average velocity=
Timetaken
Displacement
=
210
200
=0.95 m/sec
Answer:
From pont A to B
Distance covered=300m
Displacement=300m
Time taken=2 min 30 sec=(2×60)+30=150 sec
Average speed=
Timetaken
Distance covered
=
150
300
=2 m/sec
Average velocity=
Timetaken
Displacement
=
150
300
=2 m/sec
From point A to C
Distance covered=300+100=400m
Displacement=300−100=200m
Time taken=3 min 30 sec=(3×60)+30=210 sec
Average speed=
Timetaken
Distance covered
=
210
400
=1.90 m/sec
Average velocity=
Timetaken
Displacement
=
210
200
=0.95 m/sec
Explanation: