Science, asked by jason8736, 11 months ago

Joseph jogs from 1928 the other end B of a straight 300 metre road in 2 minutes 30 seconds and then turns around and jokes on demeter back to the point see in another one minute water Joseph's average speed and velocity in jogging from A to B B from B to C

Answers

Answered by iiHYPEWOLFii
1

Velocity = dispacement / time

Speed = distance / time

a) when he jogs from A to B on a straight road,

displacement = distance = 300m

time = 2 minutes 30 seconds = 150 s

velocity = 300/150 = 2 m/s

speed = 300/150 = 2m/s

b)when he jogs from A to B and turns back to C,

displacement = 300-100 = 200m

distance = 300+100 = 400m

time = 3 minute 30 second = 210 s

velocity = 200/210 = 20/21 m/s

speed = 400/210 = 40/21 m/s

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