Question

Joseph jogs from one end A to another end B of a straight 300 m road in 2 minutes and 30 sex and then turns around and jogs 100 m back to point C in another 1 minute. What are his average speed and velocities in jogging? a) From A to B b) From A to C?

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Answer 1

Answer:

From point A to B

Distance covered=300m

Displacement=300m

Time taken=2 min 30 sec=(2×60)+30=150 sec

Average speed=TimetakenDistance covered=150300=2 m/sec

Average velocity=TimetakenDisplacement=150300=2 m/sec

From point A to C

Distance covered=300+100=400m

Displacement=300−100=200m

Time taken=3 min 30 sec=(3×60)+30=210 sec

Average speed=Distance covered/timetaken=210400=1.90 m/sec

Average velocity=Displacement/time taken=210200=0.95 m/sec

Answer 2

(a) Given, distance covered from point A to point B = 300 meters

Time taken to travel from point A to point B = 2 minutes and 30 seconds = 150 seconds

Displacement from A to B = 300 meters

We know that, Average speed
= Distance/Time Taken

Therefore, the average speed while travelling from A to B =300/150= 2m/s

and, Average velocity = displacement/distance Taken

Average velocity while travelling from A to B = 300/150= 2 m/s

(b) Distance covered from point A to point C = 300m + 100m = 400 meters

Time taken to travel from point A to point C = 2 min 30 secs + 1 min = 210 seconds

Displacement from A to C = 300m – 100m = 200 meters

Similarly, Average speed while travelling from A to C
=400/210=1.9 m/s

Average velocity while travelling from A to C =
200/210
= 0.95 m/s