Question

joseph jogs from one end A to other end B of a straight 300 m. road in 2 min 30 sec and then turns around and jogs 100 m back to point C in another 1 min. what are Joseph's average speed and velocity in jogging ( a) from A to B (b) from A to C​

Answer 1

Answer:

From point A to B

Distance covered=300m

Displacement=300m

Time taken=2 min 30 sec=(2×60)+30=150 sec

Average speed=  

Time taken  /

Distance covered  =  150  / 300

​=2 m/sec

Average velocity=  

Time taken  / Displacement  =  150  / 300

 = 2 m/sec

From point A to C

Distance covered=300+100=400m

Displacement=300−100=200m

Time taken=3 min 30 sec=(3×60)+30=210 sec

Average speed=  

Time taken /  Distance covered

​  =  210  / 400

​ =1.90 m/sec

Average velocity=  

Time taken  / Displacement

​ =  210  / 200

​=0.95 m/sec