Question

Joseph jogs from one end A to the end B of a straight 300m road in 2m 30s and then turns around and jogs 100m back to point C in another 1m. What are Joseph's average speed and velocity in jogging (a) From A to B and (b) from A to C​

Answer 1

Answer:

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Explanation:

Velocity = dispacement / time

Speed = distance / time  

a) when he jogs from A to B on a straight road,

displacement = distance = 300m

time = 2 minutes 30 seconds = 150 s  

velocity = 300/150 = 2 m/s

speed = 300/150 = 2m/s  

b)when he jogs from A to B and turns back to C,

displacement = 300-100 = 200m

distance = 300+100 = 400m

time = 3 minute 30 second = 210 s  

velocity = 200/210 = 20/21 m/s

speed = 400/210 = 40/21 m/s