Physics, asked by antasd4522, 9 months ago

Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in another 1 minute . What are Joseph's average speeds and velocities in jogging (1) from A to B (2) from A to C

Answers

Answered by hiremathjyoti139
2

Answer: A to B speed- 2 m/s velocity - 2m/s

A to C speed- 1.90m/s velocity- 0.95m/s

Explanation: A to B speed- = 300m/150s= 2 m/s

Velocity= it will be same as the motion is on a straight line that is 300m/150s=2 m/s

A to C= speed- 300m+100m/150s+60s= 1.90m/s

Velocity= 300m-100m/150s+60s= 0.95m/s

( 300-100) bcoz velocity= displacement/ total time

Answered by fa626378
1
average speed from a to b=2m/s
average velocity =2m/s

average speed from a to c=1.90m/s
average velocity from a to c=0.952m/s
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