Question

Joseph jogs from one end A to the other end B of a straight line 300m road in 2 minutes 30 seconds and then turn around and jokes 100m back to point C another another one minute what a Joseph's average speed and velocity is in jogging from A to C​

Answer 1

Answer:

given----

s1=300m

t1=2min 30 sec = 150sec

t2= 150+60sec=210sec

s2=300m + 100m = 400m

displacement1=300m

displacement 2=200m

to find---

1) avg. speed

2)avg. velocity

solution----

1) avg. speed=total s/total time

=400/210

1.904ms-¹

2)

avg. velocity=displacement/time taken

200/210

=0.952ms-¹

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