Physics, asked by shreecharanbudur, 10 months ago

JOSEPH JOGS FROM ONE END A TO THE OTHER END B OF A STRAIGHT 300 M ROAD IN 2MINUTES 30 SEC AND THEN TURNS AROUND AND JOGS 100 M BACK TO POINT C IN ANOTHER 1 MIN . WHAT ARE JOSEPH'S AVERAGE SPEED'S AND VELOCITES IN JOGGING (A) FROM A TO B OR (B) FROM A TO C?

Answers

Answered by BrainlyTornado
0

here is ur answer........

Attachments:
Answered by priyomrabhadas
2

Answer:

Here we have,

Distance from point A to B = 300 m

Time taken = 2 minute 30 second = 2 x 60 + 30 s = 150 s

Distance from point B to C = 100 m

Time taken = 1 minute = 60 s

(a)  Average speed and velocity from point A to B

2 ms -1   east  

(b)  Average speed and velocity from B to C

166 ms -1  west

hope it helps

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