JOSEPH JOGS FROM ONE END A TO THE OTHER END B OF A STRAIGHT 300 M ROAD IN 2MINUTES 30 SEC AND THEN TURNS AROUND AND JOGS 100 M BACK TO POINT C IN ANOTHER 1 MIN . WHAT ARE JOSEPH'S AVERAGE SPEED'S AND VELOCITES IN JOGGING (A) FROM A TO B OR (B) FROM A TO C?
Answers
Answered by
0
here is ur answer........
Attachments:
![](https://hi-static.z-dn.net/files/d06/e2b006298ebe16d3b7ba6e77e3b916bc.jpg)
Answered by
2
Answer:
Here we have,
Distance from point A to B = 300 m
Time taken = 2 minute 30 second = 2 x 60 + 30 s = 150 s
Distance from point B to C = 100 m
Time taken = 1 minute = 60 s
(a) Average speed and velocity from point A to B
2 ms -1 east
(b) Average speed and velocity from B to C
166 ms -1 west
hope it helps
Similar questions
Computer Science,
5 months ago
Science,
5 months ago
Science,
5 months ago
English,
11 months ago
Math,
11 months ago