Question

Joseph jogs from one end A to the other end b of a straight 300

Answer 1

Explanation:

(a) A to B

Total distance (s) from A to B = 300m

Time (t) = 2min 30s = (2 x 60) + 30 = 150s

Average speed from A to B= s/t = 300m/150 = 2m/s

Total displacement (s) from A to B = 300m

Time (t) = 2min 30s = (2 x 60) + 30 = 150s

Average velocity From A to B = s/t = 300m/150 = 2m/s

(b) A to C

Total distance (s) from A to C = 300m + 100m = 400m

Time (t) = 2min 30s + 1min = [(2 x 60) + 30] + [60] = 210s

Average speed from A to C = s/t = 400m/210 = 1.90m/s

Total displacement (s) from A to C = 200m

Time (t) = 2min 30s + 1min = [(2 x 60) + 30] + [60] = 210s

Average velocity from A to C = s/t = 200m/210 = 0.95m/s