Question

Joseph jogs from one end A to the other end B of a straight 300m road in 2 minutes 30 second and then turn around and jogs m back to point c in another 1 minute. what are Joseph average speed and velocities in jogging a from A to B and (b) from A to C​

Answer 1

Answer:

Explanation:

rom pont A to B

Distance covered=300m

Displacement=300m

Time taken=2 min 30 sec=(2×60)+30=150 sec

Average speed=TimetakenDistance covered​=150300​=2 m/sec

Average velocity=TimetakenDisplacement​=150300​=2 m/sec

From point A to C

Distance covered=300+100=400m

Displacement=300−100=200m

Time taken=3 min 30 sec=(3×60)+30=210 sec

Average speed=TimetakenDistance covered​=210400​=1.90 m/sec

Average velocity=TimetakenDisplacement​=210200​=0.95 m/sec