Question

Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in another 1 minute. What are Joseph’s average speeds and velocities in jogging (a) from A to B and (b) from A to C?
Explain the each step u do in the answer....
And I will surely mark it as brainliest.....

Answer 1

(1)

average speed from A to B

In this case the total distance travelled by the object will be AB = 300m

total time taken by the body to go form A to C = time from A to B = 2min50s = 170s

so,

average speed = 300/170 = 1.764 m/s



similarly, average velocity from A to B

here the net displacement acquired will be = AB = 300m

total time taken will be the same as previously = 170s

thus,

average velocity = 300/170 = 1.764 m/s



(2)

average speed from A to C

In this case the total distance travelled by the object will be AC = AB + BC = 300m + 100m = 400m

total time taken by the body to go form A to C = time from A to B + time from B to C = 2min50s + 1min = 3min50s = 230s

so,

average speed = 400/230 = 1.739 m/s



similarly, average velocity from A to C

here the net displacement acquired will be AC = AB - BC = 300m - 100m = 200m

total time taken will be the same as previously = 230s

thus,

average velocity = 200/230 = 0.869 m/s