Question

Joseph jogs from one end a to the other end b of a straight 300m road in 2 minutes 30 seconds and then turns another 1 minutes. what are Joseph average speed and velocities in jogging (a) from a to b and (b) from a to c ?​

Answer 1

Answer:

a)

Average Speed = 2 m s⁻¹

Average Velocity = 2 m s⁻¹

Explanation:

a)

Distance travelled = 300m

Displacement = 300m

Time taken = 2 min 30 sec   or   150 seconds

Average speed = (Total Distance) / (Total time taken)

⇒ 300 / 150

⇒ 2 m s⁻¹

Average Velocity = (Displacement) / (Total time taken)

⇒ 300 / 150

⇒ 2 m s⁻¹

b) (I couldn't understand the question as it is not completed)

Hope this answer helps you.

Answer 2

Answer:

2m s¹· is your answer.

Explanation:

answer by @MrMysteryy