Question

Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 50

seconds and then turns around and jogs 100 m back to point C in another 1 minute.

What are Joseph’s average speeds and velocities in jogging (a) from A to B and (b) from

A to C?

Answer 1

Answer:

0.95 m/sec

Explanation:

from point A to B

Distance covered= 300m

Displacement= 300m

Time taken= two min 30sec = (2×60)+30= 150sec

Average speed= Distance/Time taken = 300/150= 2m/sec

Average velocity= Displacement/Time taken = 300/150= two m/sec

From point A to C

Distance corved= 300+100 = 400m

Displacement= 300–100 = 200m

Time taken= 3min 30sec = (3×60) +30 = 210 sec

Average speed= Distance covered/Time taken = 400/210 = 1.90m/sec

Average velocity= Displacement/Time taken = 200/210 =0.95 m/sec