Question

joseph jogs from one end a to the other end b of a straight 300m road in 2 minutes 30 seconds and then turns around and jogs 100m back to point c in another 1 minute what are joseph average speed and velocities in jogging (a) from A to B and (b) fromA to C

Answer 1

Time taken in jogging a to b=t1=2min 30s=(2×60+30)s=150s
Bc =100m
Time taken in jogging from b to c,t2
1min =60s
(A) From A to B
Average speed=total distance ÷total time =300 m ÷150S=2.0m/s
Average velocity =displacement (ab)÷time =300 m ÷150s =2.0m/s
(B)From A to B
Average speed =total distance ÷total time =ab+Bc ÷t1+t2
(300+100m)÷(150+60)s=400 m/s÷210 m/s=1.9m/s
Average velocity =displacement (ac)÷time = (300-100)m÷150 +60s
200m/s ÷210m/s =0.95m/s

DONE!!!

Answer 2

Hello mate here is your answer hope it helps u