Question

Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes and 50 seconds and then turns around and jogs 100 m back to point C in another 1 minute. What is Joseph's average speed and velocity in jogging from a) A to B b) A to C?

Answer 1

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From pont A to B

Distance covered=300m

Displacement=300m

Time taken=2 min 30 sec=(2×60)+30=150 sec

Average speed=TimetakenDistance covered=150300=2 m/sec

Average velocity=TimetakenDisplacement=150300=2 m/sec

From point A to C

Distance covered=300+100=400m

Displacement=300−100=200m

Time taken=3 min 30 sec=(3×60)+30=210 sec

Average speed=TimetakenDistance covered=210400=1.90 m/sec

Average velocity=TimetakenDisplacement=210200=0.95 m/sec