Physics, asked by ragapriyaraja154, 2 months ago

Joseph jogs from one end A to the other end B of a straight . 300 m road in 2 minutes 30 seconds and then turns around and 100 m back to point c in another 1 minute. What are Joseph average speed and velocity in jogging [a] from A to B [b] from A to C ?​

Answers

Answered by sunsjjs223
2

Answer:

I know the answer please mark me as brainliast

Explanation:

It is given that Joseph jogs on a straight road of 300m in a time interval of 2 minutes and 30 seconds, which is equal to 150seconds. Therefore, when Joseph jogs from point A to point B, he covers a distance of 300m in time of 150seconds. Hence, his average speed is 300m150s=2ms−1.

Answered by akshatgautam27556dps
0
300m150s=2ms-1
Mark me brainliest
Similar questions