Joseph jogs from one end A to the other end B of a straight 300 m road in in 2 minutes 30 seconds and then turn around and jogs 100 m back to point in another 1 minute.What are Joseph's average speeds and velocities in jogging
I)From A to B
II)From A to C
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Complete answer:
(a) It is given that Joseph jogs on a straight road of 300m in a time interval of 2 minutes and 30 seconds, which is equal to 150seconds. Therefore, when Joseph jogs from point A to point B, he covers a distance of 300m in time of 150seconds. Hence, his average speed is 300m150s=2ms−1.
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Joseph jogs from one end A to the other end B of a straight 300 m road in in 2 minutes 30 seconds and then turn around and jogs 100 m back to point in another 1 minute.What are Joseph's average speeds and velocities in jogging
I)From A to B
II)From A to C
Given -
- Distance from point A to B = 300m
- Time from point A to B = 2 min 30 sec (150 sec)
- Distance from point B to C = 100 m
- Time from point B to C = 1 min (60 sec)
To find -
- Average speed of Joseph's
- Average velocity in Joseph's jogging
⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀⠀⠀
I)From A to B
- Distance from point A to B = 300m
- Time from point A to B = 150 sec
Average speed -
Average velocity -
- Displacement from point A to B = 300m(because it is a straight road and he is jogging at single direction )
- Time from point A to B = 150 sec
⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━⠀
II)From A to C
- Distance from point A to C = 300m + 100m = 400 m
- Time from point A to B = 150 sec + 60 sec = 210 sec
Average speed -
Average velocity -
- Distance from point A to C = 300m - 100m = 200 m
- Time from point A to B = 150 sec + 60 sec = 210 sec
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