Physics, asked by Tigress13, 2 months ago

Joseph jogs from one end A to the other end B of a straight 300 m road in in 2 minutes 30 seconds and then turn around and jogs 100 m back to point in another 1 minute.What are Joseph's average speeds and velocities in jogging
I)From A to B
II)From A to C​

Answers

Answered by garimagoyal80
2

Answer:

Complete answer:

(a) It is given that Joseph jogs on a straight road of 300m in a time interval of 2 minutes and 30 seconds, which is equal to 150seconds. Therefore, when Joseph jogs from point A to point B, he covers a distance of 300m in time of 150seconds. Hence, his average speed is 300m150s=2ms−1.

Answered by IlMYSTERIOUSIl
11

 \huge \text{Given Question}

Joseph jogs from one end A to the other end B of a straight 300 m road in in 2 minutes 30 seconds and then turn around and jogs 100 m back to point in another 1 minute.What are Joseph's average speeds and velocities in jogging

I)From A to B

II)From A to C

 \huge \text{Required Answer}

Given -

  • Distance from point A to B = 300m
  • Time from point A to B = 2 min 30 sec (150 sec)
  • Distance from point B to C = 100 m
  • Time from point B to C = 1 min (60 sec)

To find -

  • Average speed of Joseph's
  • Average velocity in Joseph's jogging

⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀⠀⠀

I)From A to B

  • Distance from point A to B = 300m
  • Time from point A to B = 150 sec

Average speed -

\begin{gathered}\begin{gathered}\begin{gathered} \begin{gathered}\\ \sf \mapsto \pink{ \frac{Total \: Distance \: travelled}{Total \: time \: taken} }\end{gathered} \end{gathered} \end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}\begin{gathered} \begin{gathered}\\ \sf \mapsto { \frac{300 \: m}{150 \: sec} }\end{gathered} \end{gathered} \end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}\begin{gathered} \begin{gathered}\\ \sf \mapsto \red{ 2m {s}^{ - 1}  }\end{gathered} \end{gathered} \end{gathered}\end{gathered}

Average velocity -

  • Displacement from point A to B = 300m(because it is a straight road and he is jogging at single direction )
  • Time from point A to B = 150 sec

\begin{gathered}\begin{gathered}\begin{gathered} \begin{gathered}\\ \sf \mapsto \pink{ \frac{Total \: Displacement \: travelled}{Total \: time \: taken} }\end{gathered} \end{gathered} \end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}\begin{gathered} \begin{gathered}\\ \sf \mapsto { \frac{300 \: m}{150 \: sec} }\end{gathered} \end{gathered} \end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}\begin{gathered} \begin{gathered}\\ \sf \mapsto \red{ 2m {s}^{ - 1}  }\end{gathered} \end{gathered} \end{gathered}\end{gathered}

⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━⠀

II)From A to C

  • Distance from point A to C = 300m + 100m = 400 m
  • Time from point A to B = 150 sec + 60 sec = 210 sec

Average speed -

\begin{gathered}\begin{gathered}\begin{gathered} \begin{gathered}\\ \sf \mapsto \pink{ \frac{Total \: Distance \: travelled}{Total \: time \: taken} }\end{gathered} \end{gathered} \end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}\begin{gathered} \begin{gathered}\\ \sf \mapsto { \frac{400 \: m}{210 \: sec} }\end{gathered} \end{gathered} \end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}\begin{gathered} \begin{gathered}\\ \sf \mapsto \red{ 1.9m {s}^{ - 1}  }\end{gathered} \end{gathered} \end{gathered}\end{gathered}

Average velocity -

  • Distance from point A to C = 300m - 100m = 200 m
  • Time from point A to B = 150 sec + 60 sec = 210 sec

\begin{gathered}\begin{gathered}\begin{gathered} \begin{gathered}\\ \sf \mapsto \pink{ \frac{Total \: Displacement \: travelled}{Total \: time \: taken} }\end{gathered} \end{gathered} \end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}\begin{gathered} \begin{gathered}\\ \sf \mapsto { \frac{200 \: m}{210 \: sec} }\end{gathered} \end{gathered} \end{gathered}\end{gathered}

\begin{gathered}\begin{gathered}\begin{gathered} \begin{gathered}\\ \sf \mapsto \red{ 0.95m {s}^{ - 1}  }\end{gathered} \end{gathered} \end{gathered}\end{gathered}

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