Physics, asked by akshitasharma21, 1 month ago

Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in another 1 minute. What are Joseph's average speeds and velocities in jogging :
(a) fromA to B and
(b) from A to C?

Answers

Answered by sameerkushwaha2940
1

Answer:

(a) 2m/s
(b) 1.90m/s

Explanation:

(a) from A to B , avg speed = total dis./time taken
⇒300/2×120+30                         (1 min = 60 secs)
⇒300/150
⇒2m/s


(b) from A to C , avg speed= distance b/w point a and c / time taken
⇒300+100/150+60
⇒400/210
⇒1.90m/s

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