Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in another 1 minute. What are Joseph's average speeds and velocities in jogging (a) from A to B and (b) from A to C?
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HEY DEAR ... ✌️
___________________________
Here's , Your Answer ...
=) We know ,
Velocity = Dispacement / Time
Speed = Distance / Time
⏺️a] When he jogs from A to B on a straight road,
displacement = distance = 300m
time = 2 minutes 30 seconds = 150 seconds
velocity = 300/150 = 2 m/s
speed = 300/150 = 2m/s
⏺️b] When he jogs from A to B and turns back to C,
Displacement = 300-100 = 200m
Distance = 300+100 = 400m
Time = 3 minute 30 second = 210 s
velocity = 200/210 = 20/21 m/s
speed = 400/210 = 40/21 m/s
____________________________
HOPE , IT HELPS ... ✌️
___________________________
Here's , Your Answer ...
=) We know ,
Velocity = Dispacement / Time
Speed = Distance / Time
⏺️a] When he jogs from A to B on a straight road,
displacement = distance = 300m
time = 2 minutes 30 seconds = 150 seconds
velocity = 300/150 = 2 m/s
speed = 300/150 = 2m/s
⏺️b] When he jogs from A to B and turns back to C,
Displacement = 300-100 = 200m
Distance = 300+100 = 400m
Time = 3 minute 30 second = 210 s
velocity = 200/210 = 20/21 m/s
speed = 400/210 = 40/21 m/s
____________________________
HOPE , IT HELPS ... ✌️
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