Question

Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in another 1 minute. What are Joseph's average speeds and velocities in jogging (a) from A to B and (b) from A to C?

Answer 1

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Answer 2

HEY DEAR ... ✌️

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Here's , Your Answer ...


=) We know ,
Velocity = Dispacement / Time

Speed = Distance / Time

⏺️a] When he jogs from A to B on a straight road,

displacement = distance = 300m

time = 2 minutes 30 seconds = 150 seconds

velocity = 300/150 = 2 m/s

speed = 300/150 = 2m/s

⏺️b] When he jogs from A to B and turns back to C,

Displacement = 300-100 = 200m

Distance = 300+100 = 400m

Time = 3 minute 30 second = 210 s

velocity = 200/210 = 20/21 m/s

speed = 400/210 = 40/21 m/s

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HOPE , IT HELPS ... ✌️