Joseph jogs from one end A to the other end B of a straight 300m road in 2 minutes 30 seconds and then turns around and jogs 100m back to point C in another 1 minute. What are Joseph's average speeds and velocities in jogging (a) from A to B and (b) from A to C?
Answers
Answered by
4
Answer:
A to B 2m/s A to C is 10/11 m/s
mngaur2:
Plzzzz explain
Answered by
17
Answer:
average speed from point A to B=total distance travelled/total time taken
=300/150
=2m/s
velocity from point A to B=displacement/time
= 300/150
=2m/s
average speed from point A to C=total distance travelled/total time taken
300+100/150+600
=400/210
=1.92m/s
velocity from point A to C=300-100/90
=200/90
=20/9
2.2m/s
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