Physics, asked by atulsingh092337, 9 months ago

Joseph jogs from one end A to the other end of a straight 300metres road in 2minutes 30second and then turn around and jogs 100metres back to point C in another 1minutes what is the Joseph average speed (a)from Ato B and (b)from A to C

Answers

Answered by dhimanbharadwaj0428
1

Explanation:

This was one of my favorite questions in class 8 and 9

Attachments:
Answered by disada18
0

Answer:

(a) 2 m/s

(b) 1.9 m/s

Explanation:

average speed = total distance / total time taken

(a) total distance = 300 m

    total time = 2 minutes 30 seconds = 150 seconds

average speed = 300/150 = 2 m/s

(b) total distance = 300 + 100 = 400 m

    total time = 150 seconds + 60 seconds = 210 seconds

average speed = 400/210 = 1.9 m/s

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