Joseph jogs from one end A to the other end of a straight 300metres road in 2minutes 30second and then turn around and jogs 100metres back to point C in another 1minutes what is the Joseph average speed (a)from Ato B and (b)from A to C
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This was one of my favorite questions in class 8 and 9
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Answer:
(a) 2 m/s
(b) 1.9 m/s
Explanation:
average speed = total distance / total time taken
(a) total distance = 300 m
total time = 2 minutes 30 seconds = 150 seconds
average speed = 300/150 = 2 m/s
(b) total distance = 300 + 100 = 400 m
total time = 150 seconds + 60 seconds = 210 seconds
average speed = 400/210 = 1.9 m/s
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