Joseph jogs from one in to the other end B of a straight 300m road in 2 minutes 30 seconds and then turns around and jogs 100 me back to points in other one minute water Joseph average speed and velocity is in jogging A from A to c
Answers
Answer:
From pont A to B
Distance covered=300m
Displacement=300m
Time taken=2 min 30 sec=(2×60)+30=150 sec
Average speed=TimetakenDistance covered=150300=2 m/sec
Average velocity=TimetakenDisplacement=150300=2 m/sec
From point A to C
Distance covered=300+100=400m
Displacement=300−100=200m
Time taken=3 min 30 sec=(3×60)+30=210 sec
Average speed=TimetakenDistance covered=210400=1.90 m/sec
Average velocity=TimetakenDisplacement=210200=0.95 m/ˢᵉᶜ
ᴴᵒᵖᵉ ᵗʰⁱˢ ᵐᵃʸ ʰᵉˡᵖˢ ᵘ...
ᴮʸ: ᴹⁱᶜʰᵃᵉˡ ᴶᵃᶜᵏˢᵒⁿ
Answer:
11th
Physics
Motion in a Straight Line
Speed and Velocity
Joseph Jogs from one end A ...
PHYSICS
avatar
Asked on December 27, 2019 by
Pintu Bhattacharyya
Joseph Jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in another 1 minute. What are Joseph's average speeds and velocities in jogging (a) from A to B and (b) from A to C?
MEDIUM
Share
Study later
ANSWER
From pont A to B
Distance covered=300m
Displacement=300m
Time taken=2 min 30 sec=(2×60)+30=150 sec
Average speed=
Timetaken
Distance covered
=
150
300
=2 m/sec
Average velocity=
Timetaken
Displacement
=
150
300
=2 m/sec
From point A to C
Distance covered=300+100=400m
Displacement=300−100=200m
Time taken=3 min 30 sec=(3×60)+30=210 sec
Average speed=
Timetaken
Distance covered
=
210
400
=1.90 m/sec
Average velocity=
Timetaken
Displacement
=
210
200
=0.95 m/sec