Question

Joseph jogs from point A to B of 300m in 2min 30 sec and then turns back and stops and at point C at 100m from point B in 1 min what will be his Average speed and Average velocity from Ato B and from Ato C

Answer 1

Answer:

From pont A to B

Distance covered=300m

Displacement=300m

Time taken=2 min 30 sec=(2×60)+30=150 sec

Average speed=

Timetaken

Distance covered

=

150

300

=2 m/sec

Average velocity=

Timetaken

Displacement

=

150

300

=2 m/sec

From point A to C

Distance covered=300+100=400m

Displacement=300−100=200m

Time taken=3 min 30 sec=(3×60)+30=210 sec

Average speed=

Timetaken

Distance covered

=

210

400

=1.90 m/sec

Average velocity=

Timetaken

Displacement

=

210

200

=0.95 m/sec

Explanation:

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Answer 2

Answer:

From pont A to B

Distance covered=300m

Displacement=300m

Time taken=2 min 30 sec=(2×60)+30=150 sec

Average speed=

Timetaken

Distance covered

=

150

300

=2 m/sec

Average velocity=

Timetaken

Displacement

=

150

300

=2 m/sec

From point A to C

Distance covered=300+100=400m

Displacement=300−100=200m

Time taken=3 min 30 sec=(3×60)+30=210 sec

Average speed=

Timetaken

Distance covered

=

210

400

=1.90 m/sec

Average velocity=

Timetaken

Displacement

=

210

200

=0.95 m/sec

Explanation: