Joseph's weight is two times the weight of his younger brother. Find Joseph's weight if sum of their weights is 78 kg.
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Answered by
3
Step-by-step explanation:
let x be his younger brother weight and his weight be 2x
Now, x+2x=78
implies 3x=78
implies x=78/3 =26
therefore Joseph's weight is 2×26=52 as his weight is two times greater than his younger brother
Answered by
0
Answer:
52
Step-by-step explanation:
Let weight of younger brother be X
weight of Joseph =2X
sum of their weight =78
2x+x= 78
3x =78
x=26
so weight of Joseph = 2x=52
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