Question

Joseph's weight is two times the weight of his younger brother find Joseph's weight if sum of their weight is 63 kg ?​

Answer 1

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Let His younger brother's weight= x

So, joseph's weight = 2x

As joseph's weight is two times his brother's weight .

Now ,

Sum of their both age is = 63 kg

x + 2x = 63

3x = 63

x = 21 kg

Now joseph's younger brother's weight is 21 kg

So , joseph's weight is 42 kg.

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Answer 2

Given:

Joseph's weight is two times the weight of his younger brother. Also, the sum of their weight is 63 kg.

To find:

Joseph's weight.

Solution:

Joseph's weight is 42 Kg.

To find the answer, we need to follow these steps:

Let the weight of Joseph's younger brother be x Kg.

So,

according to the question,

The weight of Joseph = (2x) Kg

Now,

As given, we have,

The sum of Joseph's weight and his younger brother's weight = 63 Kg

i.e.

$x + 2x = 63$

$3x = 63$

$x = 21 \: kg$

So, Joseph's weight

$= 2x = 2(21) = 42 \: kg$

Hence, the weight of Joseph is 42 Kg.