Joseph starts from his house to his office on motorcycle daily at fixed time.If he covers this distance at 40km/ h,he is late by 11 minute.However ,if he covers this distance at50km/h,he is late by5minute only.Find the distance between his house and the office?
Answers
Answered by
0
Answer:
50km/h.
Step-by-step explanation:
Because he was last in 11minutes
Answered by
4
Step-by-step explanation:
let his normal speed and distance between his house and office be x and d respectively
then
time taken at normal speed =d/x
when his speed is at 40 km/hr time taken for him to travel d distance =d/40
therefore
d/40 -d/x=11/60
d/x=d/40-11/60. eqn 1
when his speed is at 50km/hr time taken to cover x distance=d/50
again
d/50-d/x=5/60
d/x=d/50-5/60. eqn 2
by eqn 1 and 2 we have
d/40-11/60=d/50-5/60
d/40-d/50=11/60-5/60
5d-4d/200=11-5/60
d=6/60×200
d=20km
hence distance between house and office is 20km
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