Question

Joule
A boy records that 4000 joule of work is required to transfer 10 coulomb of charge between two points
of a resistor of 50 ohm. The current passing through it is
(a) 2 A
(b) 4A
(C) 8 A
(d) 16 A
​

Answer 1

Answer:

work done W = 4000 J

charge q = 10 C

resistance R = 50 Ω

we know that ,

W = V q

V = W/q

V = 4000 / 10

V = 400 V

According to Ohm's law,

current I = V/R

I = 400/50

I = 8 A

The current passing through it is 8 A. therefore the current in the circuit is 8 A.

Explanation:

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