Question

joule of heat is required to convert 1 kg of ice into water at temperature 0 degree Celsius​

Answer 1

Answer:

Specific heat of ice = 2100JKg−1K−1

Latent heat of fusion of ice = 3.36⋅105Jkg−1

Specific heat capacity of water = 4200Jkg−1K−1

Latent heat of vaporization of water = 2.25⋅106Jkg−1.