Question

joules law of heating effect derivation​

Answer 1

Expression for joules law of heating is given below

The amount of work done when an electric charges, move against a potential difference which is denoted by V is given by;

W=V x Q …….. (1)

From the above expression,

V=W/Q

We know that,

V=IR …….. (2)

Q=It……… (3)

Therefore,

I=Q/t

Let us substitute (2) and (3) in (1) we get,

W=(IR)(It)

W=H

Where H is the amount of heat produced, it is expressed in Joules J and I is expressed in terms of Ampere.

Therefore,

Some of the examples of heating with the electric current are as follows:

1) Heaters

2) Geyser

Answer 2

Answer:

Derivation of Joules's Law of Heating. When current is passed through a resistance some work is done.In a passive resistance the work done is equal to the amount of heat evolved in a resistance. ... Let 'W' be the amount of work done to move 'q' amount of charge through the resistance.

Explanation:

expression for joules law of heating

When current is passed through a resistance some work is done.In a passive resistance the work done is equal to the amount of heat evolved in a resistance.

Consider a battery having terminal p.d ‘V’ is connected with a resistance as shown in figure. Let ‘I’ be the amount of current in the circuit. Let ‘q’ be the charge passed through the resistance in time‘t’ second.

We know that,

Current (I)=Charge (q)Time (t)

q = It……(i)

If the potential difference between A and B is V. Then,

V = IR……(ii)

Let ‘W’ be the amount of work done to move ‘q’ amount of charge through the resistance.

So, Electric potential(V)=Workdone (W)q

or, W = qV

W=VIt……(ii)

Now, from equation (i) and (ii) and (iii),

W = It.IR

or, W = I2 RT

Heat produced, H= RT joule

In CGS system,

H=I2RTJCal$

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