joy organised a large wedding. Guests had to choose their meal from beef, chicken or vegetarian. 1/3 of the guests chose beef, 5/12 of the guests chose chicken, 69 people chose vegetarian. how many guests were at the wedding
Answers
Required Answer:-
Let the total number of people who attended the wedding be x. Obviously they have eaten the food there, As we all do the same :)
Now, According to question:
- 1/3 of the guests chose beef
- 5/12 of the guests chose chicken
- 69 people chose vegetarian
The above data can be expressed as:
- Guests who chose beef + Guests who chose chicken + Guests who were vegetarian = Total number of guests
Plugging the values according to data,
➙ x/3 + 5x/12 + 69 = x
➙ 9x/12 + 69 = x
➙ 12x/12 - 9x/12 = 69
➙ 3x/12 = 69
➙ x/4 = 69
➙ x = 276.
Hence:-
The total number of guests who attended the wedding party were:
Question -
Joy organised a large wedding. Guests had to choose their meal from beef, chicken or vegetarian. 1/3 of the guests chose beef, 5/12 of the guests chose chicken, 69 people chose vegetarian. How many guests were at the wedding ?
Given that -
1/3 of the guests chose beef
5/12 of the guests chose chicken
69 people chose vegetarian
To find -
Total guests were at the wedding.
Solution -
276 were total guests at the wedding.
Full solution -
⚔ By viewing the given that we already know that 1/3 of the guests chose beef , 5/12 of the guests chose chicken , 69 people chose vegetarian express total number of guests because if someone go to weeding then the person's surely eat food as all...!
⚔ Henceforth, 1/3 of the guests chose beef + 5/12 of the guests chose chicken + 69 people chose vegetarian = Total number of guest at weeding.
⚔ Let total number of guests be a.
⚕️ a/3 + 5a/12 + 69 = a
⚕️ 9a/12 + 69 = a
⚕️ 12a/12 - 9a/12 = 69
⚕️ 3a/12 = 69
⚕️ 1a/4 = 69
⚕️ a/4 = 69
⚕️ a = 69 × 4
⚕️ a = 276
⚕️ Total guest = 276