Question

joy organised a large wedding. Guests had to choose their meal from beef, chicken or vegetarian. 1/3 of the guests chose beef, 5/12 of the guests chose chicken, 69 people chose vegetarian. how many guests were at the wedding.,​

Answer 1

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Let the total number of people who attended the wedding be x. Obviously they have eaten the food there, As we all do the same :)

Now, According to question:

1/3 of the guests chose beef

5/12 of the guests chose chicken

69 people chose vegetarian

The above data can be expressed as:

Guests who chose beef + Guests who chose chicken + Guests who were vegetarian = Total number of guests..

Plugging the values according to data,

➙ x/3 + 5x/12 + 69 = x

➙ 9x/12 + 69 = x

➙ 12x/12 - 9x/12 = 69

➙ 3x/12 = 69

➙ x/4 = 69

➙ x = 276.

Hence:-

The total number of guests who attended the wedding party were:

Answer 2

Answer:

Let the total number of people who attended the wedding be x. Obviously they have eaten the food there, As we all do the same :)

Now, According to question:

1/3 of the guests chose beef

5/12 of the guests chose chicken

69 people chose vegetarian

The above data can be expressed as:

Guests who chose beef + Guests who chose chicken + Guests who were vegetarian = Total number of guests..

Plugging the values according to data,

➙ x/3 + 5x/12 + 69 = x

➙ 9x/12 + 69 = x

➙ 12x/12 - 9x/12 = 69

➙ 3x/12 = 69

➙ x/4 = 69

➙ x = 276.

Hence:-

The total number of guests who attended the wedding party were: