Joy organized a wedding. Guests had to choose what meal they want. 1/3 Chose beef 5/12 Chose chicken and 23 chose vegetarian. How many guests were at the party?
Plz answer for me I stuck
Answers
Answered by
6
total guests X
X/3 + 5X/12 =9X/12
total veg = 1-9X/12= 3X/12
3X/12=23
X=92
X/3 + 5X/12 =9X/12
total veg = 1-9X/12= 3X/12
3X/12=23
X=92
Answered by
3
Solution :-
Let the total number of guests at the party be 'x'.
So, according to the question.
Number of guests chose beef = (x*1)/3
= x/3
Number of guests chose chicken = (x*5)/7
= 5x/7
Number of guests chose vegetarian food = 23
Now, x = x/3 + 5x/7 + 23/1
Taking LCM of 3, 5 and 1 and then solving it.
⇒ x = (4x + 5x + 276)/12
⇒ 12*x = 9x + 276
⇒ 12x - 9x = 276
⇒ 3x = 276
⇒ x = 276/3
x = 92
Hence, there were 92 guests at the party.
Let the total number of guests at the party be 'x'.
So, according to the question.
Number of guests chose beef = (x*1)/3
= x/3
Number of guests chose chicken = (x*5)/7
= 5x/7
Number of guests chose vegetarian food = 23
Now, x = x/3 + 5x/7 + 23/1
Taking LCM of 3, 5 and 1 and then solving it.
⇒ x = (4x + 5x + 276)/12
⇒ 12*x = 9x + 276
⇒ 12x - 9x = 276
⇒ 3x = 276
⇒ x = 276/3
x = 92
Hence, there were 92 guests at the party.
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