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0
Answer:
1 + tan tan89
0
=tan(90
0
−1
0
)=cot1
0
tan88
0
=tan(90
0
−2
0
)=cot2
0
Now
tan1
0
tan2
0
tan3
0
.....tan44
0
tan45
0
tan46
0
...
........tan87
0
tan88
0
tan89
0
=tan1
0
tan2
0
tan3
0
.....tan44
0
×1×cot44
0
....
...cot3
0
cot2
0
×cot1
0
=1×1×1.....×1=10 .tan 20
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