JU 356 6. What should be added to 3- 1000 138 to get 6 ? 1000 with step by step
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माना p( x ) = x³ - ax² + 6x - a
x - a = 10
⇝ x = a
.°. शेषफल
= ( a )³ - a( a )² + 6( a ) - a
= a³ - a³ + 6a - a
= 5a
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