Math, asked by adil5916, 1 year ago

JU. JJ
y 40
7. A tin holds 16.5 litres of oil. How many such tins will be required to hold
313.5 litres of oil?
B. 1.8 m of cloth is required for a shirt. How many such shirts can be made f-
nif cloth 2m long?

Answers

Answered by Anonymous
32

Solution:

Given :

  • Capacity to hold Oil in tin = 16.5 L

So, We have to find how many tins will be required to hold 313.5 litres of oil.

Required tins to hold 313.5 litres of oil = Total lites of oil in tins ÷ capacity to hold Oil in a tin.

Required tins = 313.5 ÷ 16.5

Required tins = 19

Therefore, Required Number of tins are 19.

_____________________________

Solution:

Given:

  • Required length of metre for a shirt = 1.8 m

So, We have to find how many such shirts can be made for cloth 2m long.

Required Number of shirts for 2 m long = Total length of Shirts ÷ length of one shirt

Required Shirts = 2 ÷ 1.8

Required Shirts = 1.11 or approximately 1.

Answered by Anonymous
32

Answer:

Q7(A)

Answer: 19

Q7(B)

Answer: 1

Step-by-step explanation:

Q7. (A)

Solution:

Given,

Capacity of a tin to hold oil = 313.5 l

So, the required tins to hold 313.5 l of oil = Total litres of oil in tins / capacity of a tin to hold oil

Required number of tins = 313.5 / 16.5 = 19

So, the required number of tins = 19

.°. The required number of tins = 19

-----------------------------------------

Q7(B)

Solution:

Given,

The required length of metre for a shirt = 1.8 m

So, the required number of shirts for 2 m long = The total length of shirts / Length of one shirt = 2/1.8 = 1.11

So, the required number of shirts = 1.11

1.11 is nearest to 1 that is 1.11 is approximately equal to 1.

.°. The required number of shirts = 1

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