Question

JU° + 110º = 360°
x + 250° = 360°
(Why?)

900
x = 110°
50°
TRY THESE
110°
Fig 4.9
1. What is the sum of the measures of its exterior angles x,y,z,p,q,r?
How
(ii) interior angle
(1) exterior angle
4. Repeat this activity for the cases of
(1) a regular octagon
(i) a regular 20-gon
Fig 4.10
Example 2: Find the number of sides of a regular polygon whose each exterior angle
has a measure of 45°.
Solution: Total measure of all exterior angles = 360°
leasure of each exterior angle = 45°
360°
herefore, the number of exterior angles =
8
Take a regular hexagon Fig 4.10.
2. Is x=y=z=p=9=r? Why?
3. What is the measure of each?​

Answer 1

Answer:

Additionalknowledge

Knowledge about Quadratic equations -

★ Sum of zeros of any quadratic equation is given by ➝ α+β = -b/a

★ Product of zeros of any quadratic equation is given by ➝ αβ = c/a

★ A quadratic equation have 2 roots

★ ax² + bx + c = 0 is the general form of quadratic equation

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