Question

Juanita begins to factor an expression as shown.



x2 + 3x – 18 = (x + )(x – )

The numbers that should be placed in the boxes, from left to right, are

Answer 1

hey
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splitting the middle term
x^2×-18=-18x^2

-18x^2 can be written as 6x × - 3x

x^2+6x-3x-18
x^2-3x+6x-18
x(x-3) 6(x-3)
(x+6)(x-3)

ans is (x+6)(x-3)

hope helped
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Answer 2

Given expression :

x²+3x-18

To Fill : The given blanks.

Solution :

Let's spilt the middle term :

Multiply : -18x² ; Sum : 3x

So the term in middle will spilt in to : 6x & -3x

x² + 6 x - 3 x -18

= x(x+6) -3(x+6)

= (x+6)(x-3)

The required fill ups are :

(x+6)(x-3)