Question

Judge the equivalent resistance when the following are connected in parallel − (a) 1 Ω and 106Ω, (b) 1 Ω and 103Ω and 106Ω.
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Answer 1

Answer:

a ) 1Ω and 106Ω

    =  1 x 106Ω/ 106Ω + 1Ω  = 106/107 Ω = 0.99 Ω (approx.)

b ) 1Ω , 103Ω and 106Ω

    = 1 x 103 x 106/ 1 + 103 + 106 Ω = 10918/210 Ω = 51.99 Ω (approx.)

I may have done some calculation error so please let me know if the answer is correct