Judge the equivalent resistance when the following are connected in parallel - (a) 1 Ω and 106Ω, (b) 1Ω and 103Ω and 106Ω.
with explanation
Answers
Answered by
1
Answer:
Following
Explanation:
(a) 106/107(1/R1+ 1/R2)
(b) (1/R1 + 1/R2 + 1/R3) = 1+ 1/103 + 1/106
Answered by
0
Answer:
mark me brainliest if this helps
Attachments:
Similar questions