Physics, asked by nisharajput42, 10 months ago

Judge the equivalent resistance when the following are connected in parallel :
a) 1 ohm and 106 b) 1 ohm and 1000 ohm​

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Answered by Vishal101100
0

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a) 106×1/(106+1) = 106/107 = 0.9906 Ω

b) (1000×1)/1000+1 = 1000/1001 = 0.999 Ω

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Answered by Anonymous
1

a) 1/R = 1 + 1/106

=> 1/R = 107/106

=> R = 106/107 ohm

b) 1/R = 1 + 1/1000

=> 1/R = 1001/1000

=> R = 1000/1001 ohm

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