Judge the equivalent resistance when the following are connected in parallel: (a) 10 and 10^3 0 (b) 10, 10^2 and 10^3 0.
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Since 1Ω and 106 Ω are connected in parallel
then the equivalent resistance R will be
R1=11+1061
R=106+1106 ~ 106106
R=1Ω
Equivalent resistance is 1Ω
(b) 1Ω and 103Ω and 160Ω are in parallel
R1=11+1031+1061
R1=106106+103+1
R1=10000001001001
R=0.999Ω
Therefore, equivalent resistance =0.999Ω
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