Question

Judge the equivalent resistance when the following are connected in parallel :
(i) 1 Ω and 106 Ω,
(if) 1 Ω and 103 Ω and 106 Ω​

Answer 1

Answer:

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Answer 2

Answer:

Solution



Verified by Toppr

Since 1Ω and 106 Ω are connected in parallel 

then the equivalent resistance R will be 

R1=11+1061

R=106+1106  ~ 106106

 R=1Ω

 Equivalent resistance is 1Ω 

(b) 1Ω and 103Ω and 160Ω are in parallel

R1=11+1031+1061

R1=106106+103+1

R1=10000001001001

 R=0.999Ω 

Therefore, equivalent resistance =0.999Ω