Math, asked by dhavoix4, 3 months ago

Judy drove 20 miles from her house to a theater at an average rate of 50 miles per hour. Greg drove from
his house to the theater in 1/3 of the time it took Judy to drive to the theater, and they both arrived at the
theater at the same time. If Judy left her house at 7:30 p.m., when did Greg leave his house?​

Answers

Answered by preritagrawal08
0

Answer:

7:46 P.M.

Step-by-step explanation:

Time taken by Judy = 20/50 = 2/5 hrs. = 0.4 hrs. = 24 minutes

Time taken by Gerg = 24/3 = 8minutes

If Judy left her house at 7:30 p.m. then he reach at 7:54 P.M.

then, Gerg also arrive at 7:54 P.M. at theater

So, Gerg left his home at (7:54-0:08)P.M. = 7:46P.M.

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