Math, asked by sonalparkar01, 3 months ago

Juggie loves food. He loved everything his mother cooked and his favorite foods of all were pizzas and chocolates. There was one food he did not like and that was carrots. Juggie's mother told him that he could buy as many pizzas as he liked. But he must buy twice the number of chocolates and more carrots than chocolates and pizza put together. Each pizza cost Rs. 100. The cost of a kg of carrots is half of the pizza and four small chocolates are worth the price of one orange. How much did Juggie spend on food if the number of the pizza, chocolates, and oranges were bought in integers?​

Answers

Answered by yashika9654
1

Answer:

maybe the answer is 72

Step-by-step explanation:

its my amswer for this question

Answered by kodurichandu13
0

Answer:

The total money spent by Juggie to by his food is given by 300 + 6y.

Step-by-step explanation:

Based on given data, let us assume following values for quantities and costs.

Quantities

  • Let the number of pizzas bought be x.

From the given statement, number of chocolates will be 2x (i.e., pizzas are twice the chocolates).

  • Let the number of carrots bought be c, while c > 3x (i.e., carrots are more than chocolates and pizzas, when put together).
  • Also, let the number of oranges be z.

Cost

  • The cost of each pizzas is Rs.100.
  • Let the cost of each Chocolate be y.
  • The cost of carrots per kg is \frac{100}{2} (i.e., the cost of carrots per kg is half the rate of pizza)

        That implies, kg carrot is Rs.50.

  • The cost of each orange is 4y (i.e., the cost of four chocolates is equal to cost of one orange)

Thus, the total amount spend to buy all four products is given by the equation : 100x + 2xy + 50c + 4yz.

To get minimum amount spend to  buy, let us considered the least integer value for x. That is, x = 1.

When x = 1, c > 3(1)

That implies, c can be 4. Also, considering least quantity of oranges, z = 1.

On substituting all the values, total amount spent= 100(1) + 2(1)y + 50(4) + 4y(1)

= 300 + 6y

Therefore, the total amount spend on food is equal to 300 + 6y; while the  amount varies with each chocolate rate.

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