Julia has a role in the school play. She recorded the amount of time she practiced her lines each day this week in the table below.
On Tuesday, she practiced \dfrac23 3
2
start fraction, 2, divided by, 3, end fraction of the time that she practiced on Wednesday.
Answers
Answer:
Can you please rewrite questions so we can answer
Step-by-step explanation:
Answer: = Julia practiced \blueD{\dfrac23}
3
2
start color #11accd, start fraction, 2, divided by, 3, end fraction, end color #11accd of \purpleD{\text{Wednesday's hours}}Wednesday’s hoursstart color #7854ab, start text, W, e, d, n, e, s, d, a, y, apostrophe, s, space, h, o, u, r, s, end text, end color #7854ab on Tuesday.
She practiced \purpleD{\dfrac5{6} \text{ of an hour}}
6
5
of an hourstart color #7854ab, start fraction, 5, divided by, 6, end fraction, start text, space, o, f, space, a, n, space, h, o, u, r, end text, end color #7854ab on Wednesday.
Hint #22 / 4
\purpleD{\dfrac23}
3
2
start color #7854ab, start fraction, 2, divided by, 3, end fraction, end color #7854ab of \blueD{\dfrac56}
6
5
start color #11accd, start fraction, 5, divided by, 6, end fraction, end color #11accd is another way of saying \purpleD{\dfrac23}\times\blueD{\dfrac56}
3
2
×
6
5
start color #7854ab, start fraction, 2, divided by, 3, end fraction, end color #7854ab, times, start color #11accd, start fraction, 5, divided by, 6, end fraction, end color #11accd.
Hint #33 / 4
\begin{aligned} \blueD{\dfrac23}\text{ of }\purpleD{\dfrac56} &= \blueD{\dfrac23} \times \purpleD{\dfrac56}\\\\ &= \dfrac{\blueD2 \times \purpleD5}{\blueD3 \times \purpleD{6}}\\\\ &= \dfrac{\stackrel{\blueD1}{\cancel{\blueD2}} {}\times \purpleD5 }{ \blueD3 \times \underset{\purpleD3}{\cancel{\purpleD{6}}} } \\\\ &= \dfrac5{9} \end{aligned}
3
2
of
6
5
=
3
2
×
6
5
=
3×6
2×5
=
3×
3
6
2
1
×5
=
9
5
Hint #44 / 4
Julia practiced her lines \dfrac5{9}
9
5
start fraction, 5, divided by, 9, end fraction of an hour on Tuesday.Julia practiced \blueD{\dfrac23}
3
2
start color #11accd, start fraction, 2, divided by, 3, end fraction, end color #11accd of \purpleD{\text{Wednesday's hours}}Wednesday’s hoursstart color #7854ab, start text, W, e, d, n, e, s, d, a, y, apostrophe, s, space, h, o, u, r, s, end text, end color #7854ab on Tuesday.
She practiced \purpleD{\dfrac5{6} \text{ of an hour}}
6
5
of an hourstart color #7854ab, start fraction, 5, divided by, 6, end fraction, start text, space, o, f, space, a, n, space, h, o, u, r, end text, end color #7854ab on Wednesday.
\purpleD{\dfrac23}
3
2
start color #7854ab, start fraction, 2, divided by, 3, end fraction, end color #7854ab of \blueD{\dfrac56}
6
5
start color #11accd, start fraction, 5, divided by, 6, end fraction, end color #11accd is another way of saying \purpleD{\dfrac23}\times\blueD{\dfrac56}
3
2
×
6
5
start color #7854ab, start fraction, 2, divided by, 3, end fraction, end color #7854ab, times, start color #11accd, start fraction, 5, divided by, 6, end fraction, end color #11accd.
Hint #33 / 4
\begin{aligned} \blueD{\dfrac23}\text{ of }\purpleD{\dfrac56} &= \blueD{\dfrac23} \times \purpleD{\dfrac56}\\\\ &= \dfrac{\blueD2 \times \purpleD5}{\blueD3 \times \purpleD{6}}\\\\ &= \dfrac{\stackrel{\blueD1}{\cancel{\blueD2}} {}\times \purpleD5 }{ \blueD3 \times \underset{\purpleD3}{\cancel{\purpleD{6}}} } \\\\ &= \dfrac5{9} \end{aligned}
3
2
of
6
5
=
3
2
×
6
5
=
3×6
2×5
=
3×
3
6
2
1
×5
=
9
5
Julia practice her lines \dfrac5{9}
9
5
start fraction, 5, divided by, 9, end fraction of an hour on Tuesday.
Step-by-step explanation: